Two pieces of copper tube measure 5 3/4 in and 2 7/8 in. What is their combined length?
- 8 5/8 in
- 7 5/8 in
- 8 1/8 in
- 8 7/8 in
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A. 8 5/8 in
5 3/4 = 5 6/8. Fractions: 6/8 + 7/8 = 13/8 = 1 5/8. Whole numbers: 5 + 2 = 7. Total 7 + 1 5/8 = 8 5/8 in. Forgetting to carry the extra whole inch from 13/8 gives 7 5/8 in.
Reference: Adding mixed numbers: common denominator, then carry
An electrician cuts a 14 5/16 in piece from a 36 in length of conduit. Ignoring the width of the cut, how much conduit is left?
- 22 11/16 in
- 22 5/16 in
- 21 3/16 in
- 21 11/16 in
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D. 21 11/16 in
Borrow one inch from 36: 35 16/16 − 14 5/16 = 21 11/16 in. Subtracting only the whole numbers and keeping the fraction (22 5/16) or forgetting the borrow (22 11/16) are the usual slips.
Reference: Subtracting a mixed number from a whole number by borrowing
A pipefitter cuts three pieces measuring 12 3/8 in, 9 5/8 in and 15 1/2 in from a 48 in length of pipe. Each of the three cuts wastes 1/8 in of material. How many inches of pipe are left? Answer as a decimal.
Answer in in.
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10.125 in
Pieces: 12 3/8 + 9 5/8 + 15 1/2 = 37 1/2 in. Kerf: 3 × 1/8 = 3/8 in. Total used: 37 1/2 + 3/8 = 37 7/8 in. Left: 48 − 37 7/8 = 10 1/8 in = 10.125 in.
Reference: Adding mixed numbers and allowing for saw kerf